If p and q are (odd) twin primes and q > p then p*q^2 + (p + q) + 1 is divisible by 6; a(n) = (p*q^2 + (p + q) + 1)/6.

A151990

If p and q are (odd) twin primes and q > p then p*q^2 + (p + q) + 1 is divisible by 6; a(n) = (p*q^2 + (p + q) + 1)/6.

Terms

    a(0) =14a(1) =43a(2) =314a(3) =1029a(4) =4655a(5) =12649a(6) =36610a(7) =63084a(8) =178619a(9) =211914a(10) =441209a(11) =566275a(12) =977430a(13) =1185824a(14) =1300299a(15) =1984094a(16) =2313640a(17) =3292695a(18) =3750929a(19) =5078164a(20) =7044274a(21) =12377470a(22) =13468104a(23) =16470839a(24) =23751609a(25) =30919745a(26) =36060100a(27) =39401929

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