63084domain: NAppears in sequencesIf p and q are (odd) twin primes and q > p then p*q^2 + (p + q) + 1 is divisible by 6; a(n) = (p*q^2 + (p + q) + 1)/6.at n=7A151990Numbers k such that prime(k+1)^prime(k+3) == prime(k) mod prime(k+2).at n=35A335571