Numbers n such that 3*p(n)+2, 3*p(n+1)+2 and 3*p(n+2)+2 are consecutive primes in arithmetic progression 0,18,36 so p(n), p(n+1) and p(n+2) are in arithmetic progression 0,6,12.

A102868

Numbers n such that 3*p(n)+2, 3*p(n+1)+2 and 3*p(n+2)+2 are consecutive primes in arithmetic progression 0,18,36 so p(n), p(n+1) and p(n+2) are in arithmetic progression 0,6,12.

Terms

    a(0) =97166a(1) =134357a(2) =158925a(3) =307054a(4) =370577a(5) =398387a(6) =400667a(7) =496397a(8) =535804a(9) =760413a(10) =948882a(11) =1334783a(12) =1487146a(13) =1499094a(14) =1635138a(15) =1875994a(16) =2539226a(17) =2743664a(18) =3116200

External references