97166domain: NAppears in sequencesNumbers n such that 3*p(n)+2, 3*p(n+1)+2 and 3*p(n+2)+2 are consecutive primes in arithmetic progression 0,18,36 so p(n), p(n+1) and p(n+2) are in arithmetic progression 0,6,12.at n=0A102868a(n) = a(n-1) + a(n-2) + a([n/3]) + a([2n/3]), where a(0) = 1, a(1) = 2, a(2) = 3.at n=19A298345