Let p = n-th irregular prime, A000928(n). Then a(n) = smallest value of m such that numerator(Bernoulli(2*m)/(2*m)) / numerator(Bernoulli(2*m)/(2*m*(2*m-1))) equals p.

A092291

Let p = n-th irregular prime, A000928(n). Then a(n) = smallest value of m such that numerator(Bernoulli(2*m)/(2*m)) / numerator(Bernoulli(2*m)/(2*m*(2*m-1))) equals p.

Terms

    a(0) =574a(1) =1269a(2) =1910a(3) =3384a(4) =1185a(5) =1376a(6) =9611a(7) =4789a(8) =9670a(9) =20946a(10) =13019a(11) =11247a(12) =2689a(13) =22708a(14) =13355a(15) =45251a(16) =48407a(17) =32653a(18) =18761a(19) =38706a(20) =76391a(21) =25563a(22) =50310a(23) =79023a(24) =44948a(25) =29864a(26) =21716a(27) =71441a(28) =104339a(29) =22993

External references