104339

Appears in sequences

• Let p = n-th irregular prime, A000928(n). Then a(n) = smallest value of m such that numerator(Bernoulli(2*m)/(2*m)) / numerator(Bernoulli(2*m)/(2*m*(2*m-1))) equals p.at n=28A092291
• Composite numbers n such that every divisor of n greater than one contains the digit 0.at n=36A243819