a(n) = Lucas(4n+3) + 1, or 5*Fibonacci(2n+1)*Fibonacci(2n+2).

A081015

a(n) = Lucas(4n+3) + 1, or 5*Fibonacci(2n+1)*Fibonacci(2n+2).

Terms

    a(0) =5a(1) =30a(2) =200a(3) =1365a(4) =9350a(5) =64080a(6) =439205a(7) =3010350a(8) =20633240a(9) =141422325a(10) =969323030a(11) =6643838880a(12) =45537549125a(13) =312119004990

External references