141422325domain: NAppears in sequencesa(n) = floor(tau^n) + 1, where tau = (1 + sqrt(5))/2.at n=39A062724a(n) = Lucas(4n+3) + 1, or 5*Fibonacci(2n+1)*Fibonacci(2n+2).at n=9A081015Partial sums of A005248.at n=19A188378Partial sums of the squares of Lucas numbers (A000032).at n=19A216243