Define C(n) by the recursion C(0) = 6*i where i^2 = -1, C(n+1) = 1/(1 + C(n)), then a(n) = 6*(-1)^n/Im(C(n)) where Im(z) denotes the imaginary part of z.
A069963
Define C(n) by the recursion C(0) = 6*i where i^2 = -1, C(n+1) = 1/(1 + C(n)), then a(n) = 6*(-1)^n/Im(C(n)) where Im(z) denotes the imaginary part of z.
Terms
- a(0) =1a(1) =37a(2) =40a(3) =153a(4) =349a(5) =964a(6) =2473a(7) =6525a(8) =17032a(9) =44641a(10) =116821a(11) =305892a(12) =800785a(13) =2096533a(14) =5488744a(15) =14369769a(16) =37620493a(17) =98491780a(18) =257854777a(19) =675072621a(20) =1767363016a(21) =4627016497a(22) =12113686405a(23) =31714042788a(24) =83028441889a(25) =217371282949a(26) =569085406888
External references
- oeis: A069963