116821

Appears in sequences

• Numbers k such that k-th and (k+1)-st term of A038593 differ by 4.at n=29A038635
• Define C(n) by the recursion C(0) = 6*i where i^2 = -1, C(n+1) = 1/(1 + C(n)), then a(n) = 6*(-1)^n/Im(C(n)) where Im(z) denotes the imaginary part of z.at n=10A069963
• Numbers n such that A229964(n) = 3.at n=38A229966
• Intersection of A327653 and A327654.at n=24A327655