a(1) = 1; a(n+1) = sum of terms in continued fraction for sum{k=1 to n}[a(n+1-k)/a(k)].

Terms

a(0) =1a(1) =1a(2) =2a(3) =5a(4) =13a(5) =29a(6) =149a(7) =217a(8) =449a(9) =855a(10) =1578a(11) =2834a(12) =5445a(13) =9425a(14) =17054a(15) =30095a(16) =53610a(17) =94905a(18) =170505a(19) =300335a(20) =532606a(21) =942870a(22) =1669907a(23) =2957734a(24) =5236935a(25) =9271871a(26) =16416945a(27) =29066281a(28) =51463071a(29) =91587523