53610domain: NAppears in sequencesa(1) = 1; a(n+1) = sum of terms in continued fraction for sum{k=1 to n}[a(n+1-k)/a(k)].at n=16A057873Triangle read by rows where row n is the largest (or middle or n-th) column of the reverse pyramid summation of order n described in A359087.at n=53A360145