Start of consecutive solutions of phi(x) = phi(x+2). That is, phi(a(n)) = phi(a(n)+2) and phi(a(n)+1) = phi(a(n)+3).

A050938

Start of consecutive solutions of phi(x) = phi(x+2). That is, phi(a(n)) = phi(a(n)+2) and phi(a(n)+1) = phi(a(n)+3).

Terms

    a(0) =7a(1) =359905a(2) =5154625a(3) =5886265a(4) =2264566322a(5) =7288270322a(6) =7769878442a(7) =13180385785a(8) =189700037905a(9) =196092541922a(10) =466029676802a(11) =524476614025a(12) =593410971265a(13) =753942150745a(14) =760761410042

External references