5886265domain: NAppears in sequencesStart of consecutive solutions of phi(x) = phi(x+2). That is, phi(a(n)) = phi(a(n)+2) and phi(a(n)+1) = phi(a(n)+3).at n=3A050938Numbers k such that phi(k) + phi(k+3) = phi(k+1) + phi(k+2).at n=31A076665