73858

Appears in sequences

• Let p = n-th irregular prime, A000928(n). Then a(n) = smallest value of m such that numerator(Bernoulli(2*m)/(2*m)) / numerator(Bernoulli(2*m)/(2*m*(2*m-1))) equals p.at n=62A092291
• a(n) is the smallest k > n such that prime(k)# contains the digits of prime(n)# as a substring.at n=10A390378