73572

Appears in sequences

• Fibonacci sequence beginning 4, 26.at n=18A022386
• Let p = n-th irregular prime, A000928(n). Then a(n) = smallest value of m such that numerator(Bernoulli(2*m)/(2*m)) / numerator(Bernoulli(2*m)/(2*m*(2*m-1))) equals p.at n=30A092291
• a(n) = 288*2^n - 156.at n=8A278128