60830

Appears in sequences

• Consider recurrence b(0) = (2n+1)/2, b(n) = b(0)*floor(b(n-1)); sequence gives first integer reached.at n=37A087675
• Period of the Lucas 4-step sequence A073817 mod n.at n=45A106295
• G.f. A(x) satisfies A(x) = (1 + x)/(1 - x*A(x))^2.at n=7A379173