Consider recurrence b(0) = (2n+1)/2, b(n) = b(0)*floor(b(n-1)); sequence gives first integer reached.

A087675

Consider recurrence b(0) = (2n+1)/2, b(n) = b(0)*floor(b(n-1)); sequence gives first integer reached.

Terms

    a(0) =5a(1) =35a(2) =18a(3) =814a(4) =39a(5) =390a(6) =68a(7) =72827a(8) =105a(9) =1449a(10) =150a(11) =31887a(12) =203a(13) =3596a(14) =264a(15) =27852510a(16) =333a(17) =7215a(18) =410a(19) =208464a(20) =495a(21) =12690a(22) =588a(23) =10561998a(24) =689a(25) =20405a(26) =798a(27) =744049a(28) =915a(29) =30744

External references