54284domain: NAppears in sequencesSmallest k such that A002522(k) and A002522(k+2n) are successive primes of the form m^2+1.at n=35A245463p-INVERT of (0,1,0,1,0,1,...), where p(S) = (1 - S)^4.at n=13A291224a(n) = Sum_{k=0..floor(n/3)} binomial(n-1-2*k,k) * binomial(2*n-6*k,n-3*k).at n=9A360291