Smallest k such that A002522(k) and A002522(k+2n) are successive primes of the form m^2+1.

Terms

a(0) =2a(1) =6a(2) =84a(3) =66a(4) =26a(5) =134a(6) =40a(7) =94a(8) =986a(9) =184a(10) =1524a(11) =716a(12) =864a(13) =1246a(14) =2986a(15) =784a(16) =350a(17) =2174a(18) =4796a(19) =496a(20) =7674a(21) =13136a(22) =3390a(23) =12636a(24) =5880a(25) =9904a(26) =16446a(27) =37410a(28) =6646a(29) =10430