211564

Appears in sequences

• Start with a(1)=1; for n >= 1, a(n+1)=a(n)+a(k) with k=[n-n-th digit of "e"]. If k<0 or k=0, then a(k)=0.at n=44A133392
• Solution of the complementary equation a(n) = a(n-1) + a(n-2) + b(n-1)*b(n-2), where a(0) = 1, a(1) = 3, b(0) = 2, b(1) = 4, and (a(n)) and (b(n)) are increasing complementary sequences.at n=19A295363