Start with a(1)=1; for n >= 1, a(n+1)=a(n)+a(k) with k=[n-n-th digit of "e"]. If k<0 or k=0, then a(k)=0.

A133392

Start with a(1)=1; for n >= 1, a(n+1)=a(n)+a(k) with k=[n-n-th digit of "e"]. If k<0 or k=0, then a(k)=0.

Terms

    a(0) =1a(1) =1a(2) =1a(3) =2a(4) =2a(5) =3a(6) =3a(7) =6a(8) =6a(9) =9a(10) =10a(11) =13a(12) =16a(13) =18a(14) =36a(15) =46a(16) =56a(17) =92a(18) =128a(19) =146a(20) =202a(21) =238a(22) =476a(23) =678a(24) =724a(25) =816a(26) =1054a(27) =1200a(28) =2254a(29) =3070

External references