Define f(x) = abs(1-1/x) and sequence {b(m)} such that b(m+1) = f(b(m)). a(n) is the number of initial values b(1) such that {b(m)}'s period has length n.
A378853
Define f(x) = abs(1-1/x) and sequence {b(m)} such that b(m+1) = f(b(m)). a(n) is the number of initial values b(1) such that {b(m)}'s period has length n.
Terms
- a(0) =1a(1) =2a(2) =0a(3) =4a(4) =10a(5) =12a(6) =28a(7) =40a(8) =72a(9) =110a(10) =198a(11) =300a(12) =520a(13) =812a(14) =1350a(15) =2160a(16) =3570a(17) =5688a(18) =9348a(19) =15000a(20) =24444a(21) =39402a(22) =64078a(23) =103320a(24) =167750a(25) =270920a(26) =439128a(27) =709800a(28) =1149850a(29) =1859010
External references
- oeis: A378853