Consider the recurrence d(k) = (d(k-3)*d(k-2) + 1)/(d(k-5)*d(k-4)*d(k-3)^2*d(k-2)^2*d(k-1)), with d(0..4) = {1,1,1,2,1}. a(n) = numerator(d(2*n+1)).

A377264

Consider the recurrence d(k) = (d(k-3)*d(k-2) + 1)/(d(k-5)*d(k-4)*d(k-3)^2*d(k-2)^2*d(k-1)), with d(0..4) = {1,1,1,2,1}. a(n) = numerator(d(2*n+1)).

Terms

    a(0) =1a(1) =2a(2) =3a(3) =14a(4) =69a(5) =413a(6) =7222a(7) =90211a(8) =2577626a(9) =127385577a(10) =5092018073a(11) =655664812074

External references