For any n > 0, let b_n(n+1) = 1, and for k = 1..n, if k divides b_n(k+1) then b_n(k) = b_n(k+1) / k otherwise b_n(k) = b_n(k+1) * k; a(n) = b_n(1).

A374317

For any n > 0, let b_n(n+1) = 1, and for k = 1..n, if k divides b_n(k+1) then b_n(k) = b_n(k+1) / k otherwise b_n(k) = b_n(k+1) * k; a(n) = b_n(1).

Terms

    a(0) =1a(1) =2a(2) =6a(3) =6a(4) =30a(5) =20a(6) =140a(7) =70a(8) =70a(9) =7a(10) =77a(11) =8316a(12) =108108a(13) =858a(14) =5720a(15) =1430a(16) =24310a(17) =48620a(18) =923780a(19) =46189a(20) =3879876a(21) =176358a(22) =4056234a(23) =2704156a(24) =676039a(25) =104006a(26) =312018a(27) =44574a(28) =1292646a(29) =4308820

External references