a(n) = [x^n] 1/(1 + x) * Legendre_P(n, (1 - x)/(1 + x))^(-n-1) for n >= 0.
A364302
a(n) = [x^n] 1/(1 + x) * Legendre_P(n, (1 - x)/(1 + x))^(-n-1) for n >= 0.
Terms
- a(0) =1a(1) =3a(2) =163a(3) =23623a(4) =6751251a(5) =3219777011
External references
- oeis: A364302