a(n) = [x^n] 1/(1 + x) * Legendre_P(n, (1 - x)/(1 + x))^(-2) for n >= 0.
A364300
a(n) = [x^n] 1/(1 + x) * Legendre_P(n, (1 - x)/(1 + x))^(-2) for n >= 0.
Terms
- a(0) =1a(1) =3a(2) =73a(3) =3747a(4) =329001a(5) =44127003a(6) =8405999785
External references
- oeis: A364300