a(n) = [x^n] 1/(1 + x) * Legendre_P(n, (1 - x)/(1 + x))^(-1) for n >= 0.
A364299
a(n) = [x^n] 1/(1 + x) * Legendre_P(n, (1 - x)/(1 + x))^(-1) for n >= 0.
Terms
- a(0) =1a(1) =1a(2) =19a(3) =721a(4) =49251a(5) =5370751a(6) =859748023a(7) =190320431953
External references
- oeis: A364299