a(n) = [x^n] 1/(1 - x) * Legendre_P(n, (1 + x)/(1 - x))^(n+1) for n >= 0.

A364117

a(n) = [x^n] 1/(1 - x) * Legendre_P(n, (1 + x)/(1 - x))^(n+1) for n >= 0.

Terms

    a(0) =1a(1) =5a(2) =163a(3) =14409a(4) =2511251a(5) =730485013a(6) =320259339415

External references