a(n) = 1/(cf[0;n,n,n,...,n] - cf[0;n,n,...,n]) where the first continued fraction has n+1 terms and the second has n terms.

A352798

a(n) = 1/(cf[0;n,n,n,...,n] - cf[0;n,n,...,n]) where the first continued fraction has n+1 terms and the second has n terms.

Terms

    a(0) =1a(1) =-10a(2) =330a(3) =-21960a(4) =2551640a(5) =-461930274a(6) =120572270007

External references