G.f. A(x) satisfies: [x^n] A(x)^(n-1) = [x^n] -1/A(x)^n, for n > 1.
A352019
G.f. A(x) satisfies: [x^n] A(x)^(n-1) = [x^n] -1/A(x)^n, for n > 1.
Terms
- a(0) =1a(1) =1a(2) =3a(3) =32a(4) =813a(5) =35091a(6) =2239211a(7) =196853182a(8) =22793279166
External references
- oeis: A352019