Numbers k such that tau(k) + tau(k+1) + tau(k+2) + tau(k+3) = 16, where tau is the number of divisors function A000005.

A350686

Numbers k such that tau(k) + tau(k+1) + tau(k+2) + tau(k+3) = 16, where tau is the number of divisors function A000005.

Terms

    a(0) =12a(1) =17a(2) =19a(3) =20a(4) =26a(5) =31a(6) =211a(7) =716a(8) =1226a(9) =1436a(10) =2306a(11) =2731a(12) =2971a(13) =5636a(14) =8011a(15) =12146a(16) =12721a(17) =16921a(18) =18266a(19) =19441a(20) =24481a(21) =24691a(22) =25796a(23) =28316a(24) =30026a(25) =34651a(26) =35876a(27) =37171a(28) =45986a(29) =49681

External references