The third of four solutions to a Monthly problem asking if there exist finite sequences 1 < a(1) < a(2) < ... < a(n) such that Sum_i 1/a(i) = 1 and gcd(a(i), a(i+1)) = 1 for 1 <= i < n.
A346605
The third of four solutions to a Monthly problem asking if there exist finite sequences 1 < a(1) < a(2) < ... < a(n) such that Sum_i 1/a(i) = 1 and gcd(a(i), a(i+1)) = 1 for 1 <= i < n.
Terms
- a(0) =2a(1) =3a(2) =11a(3) =23a(4) =43a(5) =127a(6) =1771a(7) =1807a(8) =32131a(9) =3263442
External references
- oeis: A346605