Integers k>=3 such that 2^k == 2 (mod k*(k-1)*(k-2)/6).

Terms

a(0) =3a(1) =5a(2) =37a(3) =101a(4) =44101a(5) =3766141a(6) =8122501a(7) =18671941a(8) =35772661a(9) =36969661a(10) =208168381a(11) =425420101a(12) =725862061a(13) =778003381a(14) =818423101a(15) =1269342901a(16) =9049716901a(17) =27221068981a(18) =60138957061a(19) =125980182901a(20) =137330493301a(21) =314912454781a(22) =315322826869a(23) =478543291381a(24) =667933881301