a(0) = 9; thereafter a(n+1) = 3*a(n)^4 + 4*a(n)^3 for n >= 1.
A333554
a(0) = 9; thereafter a(n+1) = 3*a(n)^4 + 4*a(n)^3 for n >= 1.
Terms
- a(0) =9a(1) =22599
External references
- oeis: A333554
A333554
a(0) = 9; thereafter a(n+1) = 3*a(n)^4 + 4*a(n)^3 for n >= 1.