a(n) = (2^(A003558(n)) - A332433(n))/(2*n+1), for n >= 0.

Terms

a(0) =1a(1) =1a(2) =1a(3) =1a(4) =1a(5) =3a(6) =5a(7) =1a(8) =1a(9) =27a(10) =3a(11) =89a(12) =41a(13) =19a(14) =565a(15) =1a(16) =1a(17) =117a(18) =7085a(19) =105a(20) =25a(21) =3a(22) =91a(23) =178481a(24) =42799a(25) =5a(26) =1266205a(27) =19065a(28) =9a(29) =9099507