Let P1, P2, P3, P4 be consecutive primes, with P2 - P1 = P4 - P3 = 2. a(n) = (P1 + P2)/12 for the first occurrence of (P3 - P1)/6 = n.

A329250

Let P1, P2, P3, P4 be consecutive primes, with P2 - P1 = P4 - P3 = 2. a(n) = (P1 + P2)/12 for the first occurrence of (P3 - P1)/6 = n.

Terms

    a(0) =1a(1) =23a(2) =322a(3) =1573a(4) =495a(5) =3407a(6) =10498a(7) =85067a(8) =8113a(9) =112912a(10) =166302a(11) =28893a(12) =189052a(13) =510548a(14) =598532a(15) =812752a(16) =139708a(17) =716182a(18) =2582073a(19) =4576458a(20) =2497092a(21) =5130198a(22) =5761777a(23) =25381573a(24) =7315173a(25) =20200532a(26) =40629683a(27) =33185292a(28) =69948743a(29) =38771927

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