Cubes of the form N^3 = concat(a,b,c) with N = a+b+c; a, b, c > 0.

A328200

Cubes of the form N^3 = concat(a,b,c) with N = a+b+c; a, b, c > 0.

Terms

    a(0) =512a(1) =91125a(2) =4181062131a(3) =87824421125a(4) =93824221184a(5) =121213882349a(6) =128711132649a(7) =162324571375a(8) =171323771464a(9) =368910352448

External references