Numbers k > 1 such that 2^k == 2 (mod k) and gcd(k, 3^k - 3) = 1.

A300762

Numbers k > 1 such that 2^k == 2 (mod k) and gcd(k, 3^k - 3) = 1.

Terms

    a(0) =35333a(1) =42799a(2) =49981a(3) =60787a(4) =150851a(5) =162193a(6) =164737a(7) =241001a(8) =253241a(9) =256999a(10) =280601a(11) =452051a(12) =481573a(13) =556169a(14) =617093a(15) =665333a(16) =722201a(17) =838861a(18) =1016801a(19) =1252697a(20) =1507963a(21) =1534541a(22) =1678541a(23) =1826203a(24) =2134277a(25) =2269093a(26) =2304167a(27) =2313697a(28) =2537641a(29) =2617451

External references