Least k > 1 such that all divisors d of (k^(2n+1)+1)/(k+1) satisfy d == 1 (mod 2n+1).

Terms

a(0) =2a(1) =3a(2) =2a(3) =2a(4) =9a(5) =2a(6) =2a(7) =15a(8) =2a(9) =2a(10) =15a(11) =2a(12) =32a(13) =81a(14) =2a(15) =2a(16) =55a(17) =21a(18) =2a(19) =39a(20) =2a(21) =2a(22) =4141a(23) =2a(24) =18a(25) =51a(26) =2a(27) =551a(28) =39a(29) =2