Solution of the complementary equation a(n) = a(n-1) + a(n-3) + a(n-4) + b(n-2), where a(0) = 1, a(1) = 2, a(2) = 3, a(3) = 4, b(0) = 5, b(1) = 6, b(2) = 7, b(3) = 8, and (a(n)) and (b(n)) are increasing complementary sequences.

A295756

Solution of the complementary equation a(n) = a(n-1) + a(n-3) + a(n-4) + b(n-2), where a(0) = 1, a(1) = 2, a(2) = 3, a(3) = 4, b(0) = 5, b(1) = 6, b(2) = 7, b(3) = 8, and (a(n)) and (b(n)) are increasing complementary sequences.

Terms

    a(0) =1a(1) =2a(2) =3a(3) =4a(4) =14a(5) =27a(6) =43a(7) =71a(8) =123a(9) =205a(10) =332a(11) =541a(12) =885a(13) =1439a(14) =2330a(15) =3775a(16) =6119a(17) =9909a(18) =16036a(19) =25953a(20) =42005a(21) =67975a(22) =109990a(23) =177976a(24) =287985a(25) =465980a(26) =753977a(27) =1219970a(28) =1973968a(29) =3193959

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