Solution of the complementary equation a(n) = a(n-1) + a(n-3) + a(n-4) + b(n-3), where a(0) = 1, a(1) = 2, a(2) = 3, a(3) = 4, b(0) = 5, b(1) = 6, b(2) = 7, b(3) = 8, and (a(n)) and (b(n)) are increasing complementary sequences.
A295755
Solution of the complementary equation a(n) = a(n-1) + a(n-3) + a(n-4) + b(n-3), where a(0) = 1, a(1) = 2, a(2) = 3, a(3) = 4, b(0) = 5, b(1) = 6, b(2) = 7, b(3) = 8, and (a(n)) and (b(n)) are increasing complementary sequences.
Terms
- a(0) =1a(1) =2a(2) =3a(3) =4a(4) =13a(5) =25a(6) =40a(7) =66a(8) =114a(9) =190a(10) =308a(11) =502a(12) =821a(13) =1335a(14) =2162a(15) =3503a(16) =5678a(17) =9195a(18) =14881a(19) =24084a(20) =38980a(21) =63080a(22) =102071a(23) =165162a(24) =267250a(25) =432430a(26) =699693a(27) =1132136a(28) =1831848a(29) =2964004
External references
- oeis: A295755