Solution of the complementary equation a(n) = a(n-1) + a(n-2) + b(n-1) + b(n-2) - 3*b(n-3), where a(0) = 1, a(1) = 3, a(2) = 5, b(0) = 2, b(1) = 4, b(2) = 6, and (a(n)) and (b(n)) are increasing complementary sequences.

A295360

Solution of the complementary equation a(n) = a(n-1) + a(n-2) + b(n-1) + b(n-2) - 3*b(n-3), where a(0) = 1, a(1) = 3, a(2) = 5, b(0) = 2, b(1) = 4, b(2) = 6, and (a(n)) and (b(n)) are increasing complementary sequences.

Terms

    a(0) =1a(1) =3a(2) =5a(3) =12a(4) =18a(5) =27a(6) =41a(7) =63a(8) =98a(9) =155a(10) =247a(11) =392a(12) =628a(13) =1008a(14) =1624a(15) =2620a(16) =4228a(17) =6831a(18) =11041a(19) =17853a(20) =28874a(21) =46706a(22) =75559a(23) =122244a(24) =197778a(25) =319996a(26) =517747a(27) =837715a(28) =1355433a(29) =2193118

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