Solution of the complementary equation a(n) = 3*a(n-2) - b(n-2) + 4, where a(0) = 1, a(1) = 3, b(0) = 2, b(1) = 4, and (a(n)) and (b(n)) are increasing complementary sequences.
A295140
Solution of the complementary equation a(n) = 3*a(n-2) - b(n-2) + 4, where a(0) = 1, a(1) = 3, b(0) = 2, b(1) = 4, and (a(n)) and (b(n)) are increasing complementary sequences.
Terms
- a(0) =1a(1) =3a(2) =5a(3) =9a(4) =13a(5) =24a(6) =35a(7) =66a(8) =98a(9) =190a(10) =284a(11) =559a(12) =840a(13) =1664a(14) =2506a(15) =4977a(16) =7502a(17) =14914a(18) =22488a(19) =44723a(20) =67443a(21) =134147a(22) =202306a(23) =402417a(24) =606893a(25) =1207225a(26) =1820652a(27) =3621647a(28) =5461927a(29) =10864911
External references
- oeis: A295140