a(n) = A289670(n)/2^f(n), where f(n) = 2*floor((n-1)/3) + ((n+2) mod 3).

Terms

a(0) =2a(1) =1a(2) =1a(3) =2a(4) =2a(5) =1a(6) =4a(7) =4a(8) =3a(9) =5a(10) =4a(11) =3a(12) =10a(13) =13a(14) =12a(15) =21a(16) =18a(17) =20a(18) =43a(19) =40a(20) =39a(21) =85a(22) =71a(23) =64a(24) =146a(25) =132a(26) =116a(27) =250a(28) =231a(29) =210