Let p = n-th prime == 3 mod 8; a(n) = sum of quadratic residues mod p that are > p/2.

Terms

a(0) =0a(1) =9a(2) =44a(3) =293a(4) =461a(5) =758a(6) =1022a(7) =1799a(8) =2530a(9) =3171a(10) =4778a(11) =5068a(12) =7662a(13) =8470a(14) =9993a(15) =14097a(16) =16674a(17) =19467a(18) =20755a(19) =25701a(20) =29042a(21) =34471a(22) =37506a(23) =40661a(24) =45066a(25) =48541a(26) =54324a(27) =54224a(28) =58135a(29) =60351