a(n+2) = a(n+1) + L(n+1)*a(n), where L = Lucas number (A000032) and a(0) = a(1) = 1.
A269068
a(n+2) = a(n+1) + L(n+1)*a(n), where L = Lucas number (A000032) and a(0) = a(1) = 1.
Terms
- a(0) =1a(1) =1a(2) =2a(3) =5a(4) =13a(5) =48a(6) =191a(7) =1055a(8) =6594a(9) =56179a(10) =557323a(11) =7467340a(12) =118374617a(13) =2522858097a(14) =64196033554
External references
- oeis: A269068