Let { d_1, d_2, ..., d_k } be the divisors of n. Then a(n) = d_k^1 + d_(k-1)^2 + ... + d_1^k.

A264786

Let { d_1, d_2, ..., d_k } be the divisors of n. Then a(n) = d_k^1 + d_(k-1)^2 + ... + d_1^k.

Terms

    a(0) =1a(1) =3a(2) =4a(3) =9a(4) =6a(5) =24a(6) =8a(7) =33a(8) =19a(9) =44a(10) =12a(11) =226a(12) =14a(13) =72a(14) =68a(15) =161a(16) =18a(17) =429a(18) =20a(19) =534a(20) =98a(21) =152a(22) =24a(23) =3858a(24) =51a(25) =204a(26) =136a(27) =856a(28) =30a(29) =6534

External references