Define Z(1) = {1}, and Z(n+1) = Z(n) (+) { x+y, with x and y in Z(n) } for any n>0 (where (+) stands for the symmetric difference of two sets). Then a(n) gives the number of elements in Z(n).

A263402

Define Z(1) = {1}, and Z(n+1) = Z(n) (+) { x+y, with x and y in Z(n) } for any n>0 (where (+) stands for the symmetric difference of two sets). Then a(n) gives the number of elements in Z(n).

Terms

    a(0) =1a(1) =2a(2) =3a(3) =7a(4) =10a(5) =22a(6) =42a(7) =87a(8) =170a(9) =342a(10) =686a(11) =1365a(12) =2727a(13) =5468a(14) =10919a(15) =21857a(16) =43680a(17) =87389a(18) =174756a(19) =349539a(20) =699039a(21) =1398115a(22) =2796191a(23) =5592422a(24) =11184795a(25) =22369639a(26) =44739229a(27) =89478503a(28) =178956950a(29) =357913967

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