a(0) = 1, then a(n) = Sum_{k = floor(log_2(n)) .. n - 1} a(k).

Terms

a(0) =1a(1) =1a(2) =1a(3) =2a(4) =3a(5) =6a(6) =12a(7) =24a(8) =47a(9) =94a(10) =188a(11) =376a(12) =752a(13) =1504a(14) =3008a(15) =6016a(16) =12030a(17) =24060a(18) =48120a(19) =96240a(20) =192480a(21) =384960a(22) =769920a(23) =1539840a(24) =3079680a(25) =6159360a(26) =12318720a(27) =24637440a(28) =49274880a(29) =98549760